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how to extract number of files from directory
On Programmer » Python
3,867 words with 3 Comments; publish: Sun, 04 May 2008 13:35:00 GMT; (20093.75, « »)
You can do most system type stuff in Python and it makes it much easier.
import glob
jpgList = glob.glob("*.jpg") # the glob allows you to use wild cards in the
search
jpgCount = len(jpgList)
This gives you a list of all files that end in .jpg. You can then do a
len(jpgList) to get the number of files
John
Message
From: Marc Buehler [mailto:marc_buehler (AT) yahoo (DOT) com]
Sent:Wednesday, 12, 2005 11:10 AM
To:tutor (AT) python (DOT) org
Subject:[Tutor] how to extract number of files from directory
hi.
i'm new to Python
i would like to extract the number of JPG files
from the current directory and use that number
as a parameter in my python script.
i tried:
a = os.system('ls *JPG | wc -l')
when i do:
print a
i get '0'.
what am i missing?
marc
The apocalyptic vision of a criminally insane charismatic cult leader
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- 3 Comments
- 10/12/05, Ertl, John <john.ertl (AT) fnmoc (DOT) navy.milwrote:
You can do most system type stuff in Python and it makes it much easier.
import glob
jpgList = glob.glob("*.jpg") # the glob allows you to use wild cards in
the
search
jpgCount = len(jpgList)
This gives you a list of all files that end in .jpg. You can then do a
len(jpgList) to get the number of files
John
glob seems to be a good idea, but is there a way to do it
case-insensitively, i.e., .jpg and .JPG?
it may be slower than glob, but i'm finding myself thinking more like
len([i for i in os.listdir('tmp') if i.lower().endswith('.jpg')])
now, anyone with a solution for .jpg, .JPG, .jpeg, *and* .JPEG?
-- wesley
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
"Core Python Programming", Prentice Hall, (c)2006,2001
http://corepython.com
wesley.j.chun :: wescpy-at-gmail.com <http://wescpy-at-gmail.com>
cyberweb.consulting : silicon valley, ca
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#1; Sun, 04 May 2008 13:36:00 GMT
- w chun wrote:
glob seems to be a good idea, but is there a way to do it
case-insensitively, i.e., .jpg and .JPG?
it may be slower than glob, but i'm finding myself thinking more like
len([i for i in os.listdir('tmp') if i.lower().endswith('.jpg')])
now, anyone with a solution for .jpg, .JPG, .jpeg, *and* .JPEG?
glob.glob('*.[jJ][pP][eE]?[gG]') ?
or maybe (not sure this is legal; I'm pretty sure it's ugly :-)
len([i for i in os.listdir('tmp') for suffix in ['.jpg', '.jpeg'] if i.lower().endswith(suffix)])
Kent
-- wesley
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
"Core Python Programming", Prentice Hall, (c)2006,2001
http://corepython.com
wesley.j.chun :: wescpy-at-gmail.com <http://wescpy-at-gmail.com>
cyberweb.consulting : silicon valley, ca
http://cyberwebconsulting.com
Tutor maillist - Tutor (AT) python (DOT) org
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#2; Sun, 04 May 2008 13:37:00 GMT
- glob seems to be a good idea,
Yep, I got my glob and listdir mixed up earlier
it may be slower than glob, but i'm finding myself thinking more like
len([i for i in os.listdir('tmp') if i.lower().endswith('.jpg')])
now, anyone with a solution for .jpg, .JPG, .jpeg, *and* .JPEG?
Sounds like a job for a regex?
Alan G.
Tutor maillist - Tutor (AT) python (DOT) org
#3; Sun, 04 May 2008 13:38:00 GMT